Steps followed:
1. get an input year from user
2. Check if the given year is leap year if((Year % 400 == 0) or (Year % 100 != 0) and (Year % 4 == 0))
3. print result

Program

#Python Program to Check Leap Year

   

# Taking an input year from user  

Year = int(input("Enter the number: "))

# Checking if the given year is leap year  

if((Year % 400 == 0) or  

    (Year % 100 != 0) and  

    (Year % 4 == 0)):   

    print("Given Year is a leap Year");  

# Else it is not a leap year  

else:  

    print ("Given Year is not a leap Year")

Output

Enter the number: 2022

Given Year is not a leap Year

 

Enter the number: 2000

Given Year is a leap Year

► Python Program to Check Leap Year